use the rules because that naming ionic compounds. Write the exactly formula for an ionic compound.

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Names the Binary ionic Compounds

After finding out a couple of more details about the surname of individual ions, you will be a action away indigenous knowing how to surname ionic compounds. This section starts the formal research of nomenclature, the organized naming of ubraintv-jp.comical compounds.

Naming Ions

The name of a monatomic cation is simply the surname of the element followed by words ion. Thus, Na+ is the salt ion, Al3+ is the aluminum ion, Ca2+ is the calcium ion, and so forth.

We have seen the some elements lose various numbers that electrons, producing ions of different charges (Figure 4.4.1) . Iron, for example, can form two cations, every of which, when an unified with the very same anion, provides a different compound with distinctive physical and ubraintv-jp.comical properties. Thus, we need a different name for each stole ion to identify Fe2+ native Fe3+. The same worry arises for other ions with more than one feasible charge.

There room two ways to do this distinction. In the simpler, more contemporary approach, called the Stock device (Table \(\PageIndex1\)), one ion’s optimistic charge is shown by a roman numeral in parentheses ~ the aspect name, followed by the word ion. Thus, Fe2+ is dubbed the iron(II) ion, if Fe3+ is dubbed the iron(III) ion. This device is supplied only for elements that type more 보다 one typical positive ion. We carry out not call the Na+ ion the sodium(I) ion since (I) is unnecessary. Sodium develops only a 1+ ion, so over there is no ambiguity about the name sodium ion.

Table \(\PageIndex1\): The modern and common System of Cation names ElementStemCharge

Modern Name

(Stock System)

Common Name
iron ferr- 2+ iron(II) ion ferrous ion
3+ iron(III) ion ferric ion
copper cupr- 1+ copper(I) ion cuprous ion
2+ copper(II) ion cupric ion
tin stann- 2+ tin(II) ion stannous ion
4+ tin(IV) ion stannic ion
lead plumb- 2+ lead(II) ion plumbous ion
4+ lead(IV) ion plumbic ion
chromium chrom- 2+ chromium(II) ion chromous ion
3+ chromium(III) ion chromic ion
gold aur- 1+ gold(I) ion aurous ion
3+ gold(III) ion auric ion

The second system, referred to as the common system, is not conventional yet is quiet prevalent and used in the health sciences. This system recognizes that numerous metals have two common cations. The usual system uses two suffix (-ic and -ous) that room appended come the stem of the aspect name. The -ic suffix to represent the greater of the 2 cation charges, and the -ous suffix to represent the lower one. In plenty of cases, the stem that the facet name originates from the Latin surname of the element. Table \(\PageIndex1\) perform the aspects that usage the typical system, together with their particular cation names.

Table \(\PageIndex2\): part Monatomic Anions IonName
F− fluoride ion
Cl− chloride ion
Br− bromide ion
I− iodide ion
O2− oxide ion
S2− sulfide ion
P3− phosphide ion
N3− nitride ion

The surname of a monatomic anion is composed of the stem the the aspect name, the suffix -ide, and then words ion. Thus, together we have currently seen, Cl− is “chlor-” + “-ide ion,” or the chloride ion. Similarly, O2− is the oxide ion, Se2− is the selenide ion, and also so forth. Table \(\PageIndex2\) lists the names of some common monatomic ions.

Example \(\PageIndex1\)

Name each ion.

Ca2+ S2− Cu+


the calcium ion the sulfide ion the copper(I) ion or the cuprous ion

Exercise \(\PageIndex1\)

Name each ion.

Fe2+ Fe3+ Ba2+ Answer a: iron(II) ion Answer b: iron(III) ion Answer c: barium ion

Example \(\PageIndex2\)

Write the formula for each ion.

the bromide ion the cupric ion the magnesium ion


Br− Cu2+ Mg2+

Exercise \(\PageIndex2\)

Write the formula for each ion.

the fluoride ion the stannous ion the potassium ion Answer a: F- Answer b: Sn 2+ Answer c: K+

Naming Binary Ionic Compounds with a steel that creates Only One form of Cation

Now that us know just how to surname ions, we are prepared to surname ionic compounds. A binary ionic link is a compound created of a monatomic steel cation and a monatomic nonmetal anion. The metal cation is called first, adhered to by the nonmetal anion as portrayed in figure \(\PageIndex1\) for the link BaCl2. The word ion is dropped native both parts.

Figure \(\PageIndex1\) Naming \(BaCl_2\)

Subscripts in the formula do not affect the name.

Naming Binary Ionic Compounds v a steel That Forms more Than One type of Cation

If girlfriend are given a formula for an ionic compound whose cation deserve to have much more than one possible charge, friend must an initial determine the charge on the cation prior to identifying its exactly name. For example, take into consideration FeCl2 and FeCl3 . In the very first compound, the steel ion has actually a 2+ charge because there are two Cl− ions in the formula (1− fee on each chloride ion). In the 2nd compound, the steel ion has actually a 3+ charge, as indicated by the 3 Cl− ions in the formula. These space two different compounds that need two various names. By the share system, the names are iron(II) chloride and also iron(III) chloride (Figure \(\PageIndex2\)).

number \(\PageIndex2\) specify name the \(FeCl_2\) and also \(FeCl_3\) link in the modern/stock system.
Name the cation (metal) + (Roman character in parenthesis) + Base surname of anion (nonmetal) and also -ide

If we were to use the stems and also suffixes of the common system, the names would certainly be ferrous chloride and ferric chloride, dong (Figure \(\PageIndex3\)) .

number \(\PageIndex3\) specify name the \(FeCl_2\) and \(FeCl_3\) compound in the old/common System.
"Old" base name of cation (metal) and also -ic or -ous + Base name of anion (nonmetal) and also -ide

-ous (for ions with reduced charge)


-ic (for ions with greater charge)


Exercise \(\PageIndex4\)

Name every ionic compound.

AuCl3 PbO2 CuO Answer a: gold(III) chloride Answer b: lead(IV) oxide Answer c: copper(II) oxide

Figure \(\PageIndex4\) is a synopsis of just how to name an easy ionic compounds.

Figure \(\PageIndex4\): A guide to Naming basic Ionic Compounds.

Exercise \(\PageIndex5\)

Name every ionic compound.

ZnBr2 Al2O3 AuF3 AgF Answer a: zinc bromide Answer b: aluminum oxide Answer c: gold(III) fluoride or auric fluoride Answer d: silver- fluoride

Writing formulas of Ionic Compounds

Ionic compounds do not exist together molecules. In the hard state, ionic compounds space in decision lattice containing countless ions each of the cation and also anion. An ionic formula, like \(\ceNaCl\), is an empirical formula. This formula merely shows that salt chloride is do of an equal number of sodium and chloride ions. Sodium sulfide, another ionic compound, has the formula \(\ceNa_2S\). This formula indicates that this link is made up of double as countless sodium ions as sulfide ions. This section will teach you just how to find the correct proportion of ions, so that you deserve to write a correct formula.

If you understand the surname of a binary ionic compound, you can write the ubraintv-jp.comical formula. Start by composing the metal ion with its charge, complied with by the nonmetal ion through its charge. Due to the fact that the in its entirety compound should be electrically neutral, decide how numerous of every ion is necessary in order because that the optimistic and negative charge come cancel each other out.

Example \(\PageIndex5\): Aluminum Nitride and also Lithium Oxide

Write the formula because that aluminum nitride and lithium oxide.


Write the formula because that aluminum nitrideWrite the formula because that lithium oxide
1. Write the symbol and also charge the the cation (metal) first and the anion (nonmetal) second. \(\ceAl^3+ \: \: \: \: \: \ceN^3-\) \(\ceLi^+ \: \: \: \: \: \ceO^2-\)
2. Use a multiplier to do the complete charge that the cations and also anions same to each other.

total fee of cations = complete charge the anions

1(3+) = 1(3-)

+3 = -3

total charge of cations = total charge the anions

2(1+) = 1(2-)

+2 = -2

3. Use the multipliers together subscript for each ion. \(\ceAl_1N_1\) \(\ceLi_2O_1\)
4. Write the last formula. Leave the end all charges and all subscripts that are 1. \(\ceAlN\) \(\ceLi_2O\)

Example \(\PageIndex6\): The Crisscross method for command (IV) oxide

Write the formula because that lead (IV) oxide.


Crisscross MethodWrite the formula for lead (IV) oxide
1. Compose the symbol and charge that the cation (metal) very first and the anion (nonmetal) second. \(\cePb^4+ \: \: \: \: \: \ceO^2-\)
2. Transpose just the number of the optimistic charge to become the subscript of the anion and the number only of the negative charge to end up being the subscript that the cation.
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3. Minimize to the lowest ratio. This action is no necessary.

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4. Write the last formula. Leave the end all every subscripts that are 1. \(\ceNa_2S\)