A excellent area to begin once trying to figure out the electron configuration of an ion is the electron configuration of the neutral parent atom.

In this situation, titanium, #"Ti"#, is situated in period 4, team 4 of the periodic table and has an atomic number of #22#.

This suggests that a neutral titanium atom will contain #22# proloads in its nucleus and also #22# electrons bordering its nucleus.

Thus, the electron configuration of a neutral titanium atom should account for #22# electrons. Consequently, the electron configuration of the titanium(II) cation, #"Ti"^(2+)#, must account for #20# electrons, since this cation is developed as soon as a neutral titanium atom loses #2# electrons.

The electron configuration of a neutral titanium atom looks choose this

#"Ti: " 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^2#

Now, it"s essential to keep in mind that this notation for the electron configuration is advantageous once adding electrons to develop an atom "from scratch" bereason in that case, the #4s# orbital is filled before the #3d# orbitals.

That happens because the empty #3d# orbitals are actually higher in power than the empty #4s# orbital, as checked out here

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However, when the #4s# orbital is filled, it becomes higher in power than the #3d# orbitals.


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This means that when titanium loses electrons, it does so from the #4s# orbital first.

#"Ti: " 1s^2 2s^2 2p^6 3s^2 3p^6 3d^2 4s^2#

Thus, the 2 electrons that are shed once the #"Ti"^(2+)# is formed will certainly come from the #4s# orbital, which implies that the electron configuration of the cation is

#color(green)(|bar(ul(color(white)(a/a)color(black)("Ti"^(2+): 1s^2 2s^2 2p^6 3s^2 3p^6 3d^2)color(white)(a/a)|)))#

If you desire, you have the right to usage the noble gas shorthand notation to write

#color(green)(|bar(ul(color(white)(a/a)color(black)("Ti"^(2+): <"Ar"> 3d^2)color(white)(a/a)|)))#

Here #<"Ar"># represents the electron configuration of argon, the noble gas that comes instantly before titanium in the routine table.