Hi,In BIDMAS (brackets, indices, division, multiplication, addition, subtraction) it shows plainly that indices have to happen prior to subtraction, for this reason why go -52=25? due to the fact that the real working (according to BIDMAS) have to put the square first and then placed the negative sign on, i m sorry would median the price is -25. And also then for \sqrtnegative numbers, you have to use i; imagine numbers. And i is same to the square source of -1. But surely the \sqrt-25 is -5, not 5.I to be told that BIDMAS was correct in every situation and should be applied to every mathematics. Is this wrong? If so, is over there anything else it shouldn"t be used to?
I would check out -52 as -(52)=-25. Why carry out you think it would be 25?This translate is even much more obvious v formulas prefer b2=c2-a2.##\sqrt-25=\pm 5i##, it is neither -5 nor 5.

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Haha, i think that since I was taught the if you square a an unfavorable number it becomes a positive since I to be told the -52 is the same as -5*-5, and if friend multiply two negatives you acquire a positive.
You 2 contradict every other here I"m pretty sure; mfb said that ##\sqrt-25=\pm 5i## however then Borek, if you say the -52=25, your logic would indicate that the turning back of this would mean that ##\sqrt-25=-5##. What"s odd is that you both agree that -52=-25, you just don"t agree top top the reverse. Am ns incorrect somewhere here, due to the fact that my brain is fixated on the fact that if 52=-25 that ##\sqrt-25=-5##?Please help... I"m descending into madness.
AlfieD, -52 is -(5*5), not (-5)*(-5) (this is what everyone above is saying). In specific when you calculate -52 you space NOT squaring something and also getting -25, you are squaring something and then doing secondary operation (taking negatives) to get to -25.
when you calculate -52 you are NOT squaring something and also getting -25, you room squaring something and also then doing second operation (taking negatives) to acquire to -25.
Ah, OK, thanks for the clarification. I will certainly make note to tell my teacher he was W.R.O.N.G. Not correct the next time I view him! :D
Thanks, never ever even considered the two various ones (stupid brain). Walk \sqrt fall under a classification in BIDMAS despite (indices because that example)? Or is it fully separate and undefined come BIDMAS?
Thanks, never even taken into consideration the two various ones (stupid brain). Go \sqrt autumn under a category in BIDMAS though (indices because that example)? Or is it completely separate and undefined to BIDMAS?
There is no ambiguity involved in the calculate order for square roots, castle are similar to brackets. Calculate whatever under the square root, climate take the root out of this value.
There is no ambiguity affiliated in the calculation order because that square roots, lock are similar to brackets. Calculate every little thing under the square root, then take the root out of this value.
Thanks, never even taken into consideration the two various ones (stupid brain). Go \sqrt fall under a classification in BIDMAS though (indices for example)? Or is it totally separate and also undefined to BIDMAS?
To include to the comment the mfb, note that the square root √ is far better (in the sense of "more general") expressed as 1/2. Thus, changing ##\sqrta+b## into ##(a+b)^1/2##, you have the right to easily use BIDMAS.

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Ah, OK, thanks for the clarification. I will make note to tell mine teacher he to be W.R.O.N.G. Wrong the next time I see him! :D