Once you\"ve learned about negative numbers, friend can also learn about an unfavorable powers. A negative exponent just method that the basic is on the wrong side of the fraction line, therefore you need to flip the base to the other side. For instance, \"x–2\" (pronounced as \"ecks come the minus two\") just way \"x2, however underneath, as in 1/(x2)\".

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write x–4 using just positive exponents.

I understand that the an adverse exponent way that the base, the x, belongs on the various other side the the portion line. Yet there isn\"t a portion line!


To deal with this, I\"ll very first convert the expression into a portion in the method that any expression deserve to be converted right into a fraction: by placing it over \"1\". That course, as soon as I relocate the base to the other side of the fraction line, there will be nothing left on top. But because anything can additionally be regarded as gift multiplied by 1, I\"ll leave a 1 top top top.

Here\"s what that looks like:


Once ns no longer needed the \"1\" underneath (to create the fraction), ns omitted it, since I had actually the change expression underneath, and the \"times one\" doesn\"t change anything.

write x2 / x–3 using just positive exponents.

Only one of the terms has actually a an adverse exponent. This means that I\"ll just be relocating one of these terms. The term through the an unfavorable power is underneath; this means that I\"ll be moving it up top, to the various other side that the portion line. There already is a hatchet on top; I\"ll be making use of exponent rule to integrate these 2 terms.

Once I relocate that denominator increase top, i won\"t having anything left under (other than the \"understood\" 1), so I\"ll drop the denominator.


The an unfavorable power will end up being just \"1\" as soon as I relocate the base to the other side the the fraction line. Anything come the power 1 is just itself, so I\"ll be able to drop this power as soon as I\"ve moved the base.


Make certain you know why the \"2\" above does not relocate with the variable: the an adverse exponent is only on the \"x\", so just the x moves..

I\"ve acquired a number inside the strength this time, and a variable, for this reason I\"ll should remember to leveling the number squaring.

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Unlike the previous exercise, the parentheses expected that the an unfavorable power did indeed use to the three and the variable.

create (-5x-1)/(y3) using only positive powers.

The \"minus one\" power on the x way that I\"ll require to move that x to the various other side the the portion line. Yet the \"minus\" ~ above the 5 means only that the 5 is negative. This \"minus\" is not a power, so it doesn\"t say anything around moving the 5 anywhere!